Question

if sin^A +sin^B = sin^C prove triangle ABC is right angled​

Answer 1

Correct option is

C

Right angled

Given, sinAsinB=

c

2

ab

⇒c

2

=

sinAsinB

ab

=(

sinA

a

)(

sinB

b

)

⇒c

2

=(

sinC

c

)

2

(∵

sinA

a

=

sinB

b

=

sinC

c

)

⇒sin

2

C=1

⇒C=90

Hence, ΔABC is a right angled triangle.