If sin A+ sinB+sinC=3 then find the value
Cos A+cos B + cos C
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Hi Bro!
sin A + sin B + sin C = 3
We know that the maximum value of sin is 1.
Therefore,
sin A = 1, sin B = 1, sin C = 3 (this satisfies the given equation)
The value of sin is 1 when the angle is 90 degrees.
That means, A = B = C = 90°
Now,
cos A + cos B + cos C = cos 90° + cos 90° + cos 90°
= 0 + 0 + 0
= 0
I hope that it may help you!
sin A + sin B + sin C = 3
We know that the maximum value of sin is 1.
Therefore,
sin A = 1, sin B = 1, sin C = 3 (this satisfies the given equation)
The value of sin is 1 when the angle is 90 degrees.
That means, A = B = C = 90°
Now,
cos A + cos B + cos C = cos 90° + cos 90° + cos 90°
= 0 + 0 + 0
= 0
I hope that it may help you!
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