Question

If sin A = ⅓ then find the value of cos A cosec A + tan A sec A​

Answer 1

Answer:

6/√2

Step-by-step explanation:

sinA=1/3⇒cosecA=3

We have,

cosA=2√2/3 (∵1²+(2√2)²=3²)

⇒secA=3/2√2

∴tanA=1/2√2

∴2√2/3×3+1/2√2×3/2√2

=2√2+3/8

=16√2+3/8