Question

If Sin A= ⅘, write all trigonometric ratios.

Answer 1

sin A = 4/5

so , sin = p/h

p = 4k (perpendicular)

h = 5k (hypotenuse)

b = under root (4k^2 + 5k^2)

b = 3k (base)

cos A = b/h = 3k/5k = 3/5

tan A = p/b = 4k/k = 4/3

cosec A = h/p= 5k/4k = 5/4

sec A =  h/b = 5k/3k = 5/3

cot A = b/p = 3k/4k = 3/4

(I'm in 9th standard if there is any mistake then sorry)

Answer 2

Answer:

Step-by-step explanation:

Solution:

Given,

∠A = 90°, a = 25 cm, b = 7 cm

Thus, BC = 25 cm and CA = 7 cm

RBSE class 9 maths chapter 14 imp que 1 sol

In right triangle ABC,

AB2 + AC2 = BC2

AB2 = BC2 – AC2

AB = √(25)2 – (7)2

= √(625 – 49)

= √576

AB = 24

For acute angle B, trigonometric ratios are:

sin B = AC/BC = 7/25

cos B = AB/BC = 24/25

tan B = AC/AB = 7/24

cosec B = 1/sin B = 25/7

sec B = 1/cos B = 25/24

cot B = 1/tan B = 24/7

For acute angle C, trigonometric ratios are:

sin C = AB/BC = 24/25

cos C = AC/BC = 7/25

tan C = AB/AC = 24/7

cosec C = 1/sin C = 25/24

sec C = 1/cos C = 25/7

cot C = 1/tan C = 7/24

_____________ii method________

if sin A=4/5

Cos A=3/5

Tan A =4/3

Cosec A=5/4

Sec A=5/3

Cot A =3/4

____________________________

Hope it helps

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