Question

if sin alfa =1/2 & alfa is an acute angle than find the value of 3cos alfa and 4cos cube alfa

Answer 1

$\sin( \alpha ) = \frac{1}{2}$
Suppose a right angled triangle with perpendicular =1 and hypotenuse =2

Then base = root 3

$\cos( \alpha ) = \frac{ \sqrt{3} }{2}$
Therefore,
$3 \cos( \alpha ) = \frac{3 \sqrt{3} }{2}$
and
$4 \cos {}^{3} ( { \alpha }) = \frac{3 \sqrt{3} }{2}$

Answer 2

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