Question

if sin alpha=3/5 and alpha + beta =90° find cos beta ​

Answer 1

Answer:

answer is same because both sum is 90

Answer 2

The value of $\cos \beta$ is equal to $\dfrac{3}{5}$.

Step-by-step explanation:

We have,

$\sin \alpha=\dfrac{3}{5}$ and α + β = 90°

To find, the value of $\cos \beta$ = ? ​

∴ $\cos \beta$

∵ α + β = 90°

⇒  β = 90° - α

∴ $\cos \beta$

= $\cos (90-\alpha)$

Using the identity,

$\cos (90-A)=\sin A$

$= \sin \alpha$

$=\dfrac{3}{5}$ [ Given by question, $\sin \alpha=\dfrac{3}{5}$ ]

∴ The value of $\cos \beta$ is equal to $\dfrac{3}{5}$.