Question

if sin Alpha/a=cos alpha/b then prove that a sin 2 alpha+bcos2 alpha=2​

Answer 1

Answer:

Please find the attachment

Answer 2

Answer:

Given

sin Alpha/a=cos alpha/b

sin Alpha=a.cos alpha/b

Since,

asin2α+bcos2α =2asinαcosα+b(1−2sin ^2 α)

= 2a^2 cos^2 alpha/ b + b (1-2a^2 cos^2 alpha/ b^2)

=2a^2 cos^2 alpha/ b + b -2a^2 cos^2 alpha/ b

2a^2 cos^2 alpha/ b + b -2a^2 cos^2 alpha/ b = b