Question

If sin alpha and cos beta are the roots of the equation ax^2+bx+c=0, then find b^2.

Answer 1

${\huge{\mathfrak{Answer :-}}}$

$<u><b>$

===>>Sin alpha + cos alpha= -b/a

Sin alpha x cos alpha= c/a

(sin alpha + cos alpha)square =b2/a2

Sin2alpha + cos2alpha + 2sin alpha x cos alpha = b2/a2

1+2c/a = b2/a2

(a+2c)/a = b2/a2

a(a+2c)=b2

a2+2ac=b2

$<marquee>Hope it helps uh$