CBSE BOARD X, asked by LOLEMOTE, 5 hours ago

if sin alpha+beta=1,sin alpha-beta=1/2,alpha,beta belongs to[0, pie/2] then find the value of tan ( alpha+2 beta) × tan( 2alpha+ beta)

Answers

Answered by lokeshnandigam69
17

Answer:

ANSWER –_/3/3

HOPE IT HELPS YOU DEAR BRAINLIEST

Attachments:
Answered by lokejanu1221
22

</p><p>[tex]\huge\pink{ANS}\blue{WER}

[/tex]

hey mate here is ur answer--------------------------------------

 \sin( \alpha  +  \beta ) = 1

and

\sin( \alpha  -  \beta ) = 1 \div 2

\sin( \alpha  +  \beta ) =  \sin90 \: and \sin( \alpha  -  \beta ) =  \sin30

( \alpha  +  \beta ) = 90 \: and \ \:  \alpha  -  \beta  = 30

\huge\red{By  \: adding}

\alpha  = 60 \: and \ \:  \beta  = 30

\tan( \alpha  + 2 \beta ) =  \tan(60 + 2x \: 30) =  \tan(120)

</u></em></p><p><em><u>[tex] \tan( \alpha  +  2 \beta ) =  -   \sqrt{3}

Now ,

 \tan(2 \alpha  +  \beta )  =  \tan(2 \times 60 + 30)  =  \tan(150)

 \tan(2 \alpha  +  \beta )  =  -  \sqrt{3}  \div 3

I hope this helps u

have a nice day .

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