Question

if sin (alpha +beta ) =1 ,sin (alpha-beta),alpha beta = 0 radius \2 then find the value of tan (alpha+2 beta), tan(2 alpha+beta)

Answer 1

Answer:

sin(α+β)=1,sin(α−β)=1/2

⇒α+β=π/2,α−β=π/6

⇒α= π

3

,β= π

6

=tan(α+2β)tan(2α+β)

=tan( 2π )tan(5π )

3 6

=(−3)(−1/3)=1