Question

if sin alpha +cos alpha =2 find the value of sin^10alpha +cos^10alpha​

Answer 1

sinα+cosecα=2

sinα+sinα1=2

sin2α+1=2sinα

sin2α−2sinα+1=0

(sinα−1)2=0

sinα=1

hence,

cosecα=sinα1=1

now,

sinnα+cscnα=(1)n+(1)n=1+1=2

Answer:

=2