If sin alpha+sin beta+ sin gama=3 then find sin^3alpha+sin^3beta+sin^3gama=
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1
Answer:
3
Step-by-step explanation:
since , max value of sine is 1.
sin alpha = sin beta = sin gamma = 1( from given condition).
So, (1)^3 + (1)^3 + (1)^3 = 1 + 1 + 1 = 3
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