Math, asked by sridharvadali32, 1 day ago

If sin alpha+sin beta+ sin gama=3 then find sin^3alpha+sin^3beta+sin^3gama=

Answers

Answered by pnagesh7535
1

Answer:

3

Step-by-step explanation:

since , max value of sine is 1.

sin alpha = sin beta = sin gamma = 1( from given condition).

So,  (1)^3 + (1)^3 + (1)^3 = 1 + 1 + 1 = 3

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