Question

if sin B= 12/13, then find cot B.

Answer 1

Here is ur ans. Hope it helps u.

Answer 2

Answer:

$\red { Value \: of \: Cot B }\green {=\frac{5}{12}}$

Step-by-step explanation:

$Given \: sinB = \frac{12}{13}$

$\implies \frac{1}{cosec B } = \frac{12}{13}$

$\implies Cosec B = \frac{13}{12} \: --(1)$

$\implies cot B = \sqrt{ cosec^{2} B - 1}$

$= \sqrt{ \left( \frac{13}{12}\right)^{2} - 1}$

$= \sqrt{ \left( \frac{169}{144}\right) - 1}$

$= \sqrt{\frac{169-144}{144}}$

$=\sqrt{\frac{25}{144}}$

$= \sqrt{\left(\frac{5}{12}\right)^{2}}$

$\green {=\frac{5}{12}}$

Therefore.,

$\red { Value \: of \: Cot B }\green {=\frac{5}{12}}$

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