If sin C = 15/17, then my dear frnds can u plz find cosC
Answers
Answered by
4
SinC =15/17 = opposite/hypotenuse
CosC= Adjesent /hypotenuse
In tri.ABC
AC°2 =AB°2+BC°2
17°2=15°2+BC°2
289=225+bc^2
BC°2= 64
BC=8
CosC=8/17
Answered by
5
Given :- sin c = 15/17
But we know that, sin θ = p/h = perpendicular/ hypotenuse
Therefore, p = 15 and h = 17
By Pythagoras Theorem,
h² = p² + b²
(17)² = (15)² + b²
289 = 225 + b²
289 - 225 = b²
b² = 64
b = √64
b = √8 * 8
b = 8
So, cos θ = b/h
Therefore, cos c = 8/17
But we know that, sin θ = p/h = perpendicular/ hypotenuse
Therefore, p = 15 and h = 17
By Pythagoras Theorem,
h² = p² + b²
(17)² = (15)² + b²
289 = 225 + b²
289 - 225 = b²
b² = 64
b = √64
b = √8 * 8
b = 8
So, cos θ = b/h
Therefore, cos c = 8/17
Anurag19:
Its my pleasure freind
Similar questions