Question

if sin C=5/13 in ∆ABC where angle B =90° ,find sin A ,cos A, cos C​

Answer 1

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Answer 2

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GIVEN :-

∠B = 90°

Sin C = 5/13

= Opposite to C/Hypotenuse

T0 FIND :-

sin A , cos A , cos C.

SOLUTION:-

Let Opposite to C = 5x

Hypotenuse = 13x

Adjacent Side = √(13x)² - (5x)²

= √169x² - 25x²

= √144x²

sinA = Opposite to C/Hypotenuse

= 12x/13x

= 12/13

cosA = Adjacent to A/Hypotenuse

= 5x/13x

= 5/13.

cosC = Adjacent to C/Hypotenuse

= 12x/13x

= 12/13.