If sinα- cosα=0, find tge value of sec(π/2-α)+cosec(π/2-α)
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Answered by
3
since
sinA - cosA=0,
then
sinA=cosA,
sinA/cosA =1,
tanA=1,
tanA=tan45°,
then
A=45°,
hence
sec(π/2-A) + cosec(π/2-A),
cosecA + secA,
cosec45° + sec45°,
√2 + √2,
2√2
sinA - cosA=0,
then
sinA=cosA,
sinA/cosA =1,
tanA=1,
tanA=tan45°,
then
A=45°,
hence
sec(π/2-A) + cosec(π/2-A),
cosecA + secA,
cosec45° + sec45°,
√2 + √2,
2√2
Answered by
3
sinα - cosα =0
sinα = cosα
α = π/4
sec(π/2 - π/4) + cosec(π/2 - π/4)
= sec(π/4) + cosec(π/4)
= √2 + √2
= 2√2
sinα = cosα
α = π/4
sec(π/2 - π/4) + cosec(π/2 - π/4)
= sec(π/4) + cosec(π/4)
= √2 + √2
= 2√2
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