If (sinθ-cosθ)=0,then sin^4θ+cos^4θ=?
Answers
Answered by
13
Step-by-step explanation:
From the above equation, we get
cosθ=sinθ
Hence
θ=45
0
Therefore
sin
4
θ+cos
4
θ
=sin
4
45
0
+cos
4
45
0
=2×(
2
1
)
4
=2×
4
1
=
2
1
Answered by
2
Answer:
sin theta - cos theta = 0
=> sin theta = cos theta
since, sin 45° = cos 45 ° = 1/√2
on comparing both the equations, theta = 45°
thus,
sin⁴ theta + cos⁴ theta =
sin⁴45° + cos⁴45°
= (1/√2)⁴ + (1/√2)⁴
= 1/4 + 1/4
= 2/4
= 1/2
Similar questions