Question

If sinѳ -cosѳ =0 then the value of ( sin^4ѳ +cos^4ѳ) is​

Answer 1

Answer:

sinx-cosx=0

i.e. x=π/4

sin⁴x+cos⁴x=(1/√2)⁴+(1/√2)⁴=1/4+1/4=1/2