If sinᶿ - cosᶿ = 1/2 then find the value of sinᶿ+cos ᶿ.
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Let sina+cosa=x...... (1)
Given
Sina-cosa =1/2..... (2)
Squaring both side and add equation 1&2
(Sina+cosa)^2+(sina-cosa)^2=(1/2)^2+x^2
Sin^2a+cos ^2+2sina ×cosa +sin^2a+cos^2a-2sina ×cosa= 1/4+x^2asinaaa
Or
1+1=1/4+x^2
X^2= 7/4
X=root 7 by 2
Hence the value of sina+cosa=root 7 by 2
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