If sinθ+cosθ= 1 then sin⁶θ+cos⁶θ is
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Answer:
Given, sinθ+cosθ=1
Squaring both sides gives,
sin 2θ+cos 2
θ+2sinθcosθ=1
⇒1+2sinθcosθ=1
⇒2sinθcosθ=0
⇒sinθcosθ=0
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