Question

If sinθ + cosθ = √2 cos θ, 0° < θ < 90°, then write the value of cot θ.

Answer 1

Answer:

Answer:sinθ+cosθ = √2cosθ

Answer:sinθ+cosθ = √2cosθsinθ/cosθ+1=√2

Answer:sinθ+cosθ = √2cosθsinθ/cosθ+1=√2sinθ/cosθ=√2-1

Answer:sinθ+cosθ = √2cosθsinθ/cosθ+1=√2sinθ/cosθ=√2-1tanθ=√2-1

Answer:sinθ+cosθ = √2cosθsinθ/cosθ+1=√2sinθ/cosθ=√2-1tanθ=√2-1cotθ=1/√2-1 OR

Answer:sinθ+cosθ = √2cosθsinθ/cosθ+1=√2sinθ/cosθ=√2-1tanθ=√2-1cotθ=1/√2-1 ORcotθ=√2+1

Answer 2

Refer the attachment

hope it helps