If sinθ.cosθ=4 , then (sinθ+cosθ²)=
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Answer:
This will help you
Step-by-step explanation:
sinθ+cosθ=a
sin
4
θ+cos
4
θ=(sin
2
θ+cos
2
θ)
2
−2sin
2
θcos
2
θ
= 1 - 2sin
2
θcos
2
θ
Now, (sinθ+cosθ)
2
=sin
2
θ+cos
2
θ+2sinθcosθ
a
2
=1+2sinθcosθ
sinθcosθ=
2
1
(a
2
−1)
Hence, substituting the value of sinθcosθ, we get,
sin
4
θ+cos
4
θ=1−
2
1
(a
2
−1)
2
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