Question

if sin ~ = cos & then what is the value of ~ + &​

Answer 1

$\large\underline{\sf{Given- }}$

• sin ~ = cos &

$\large\underline{\sf{To\:Find - }}$

• The value of ~ + &

$\begin{gathered}\Large{\sf{{\underline{Formula \: Used - }}}}  \end{gathered}$

$\rm :\longmapsto\: \boxed{ \sf \: sinx = cos(90 \degree \: - x)}$

$\large\underline{\sf{Solution-}}$

Given that

• sin ~ = cos &

• sin ~ = sin(90° - &)

• ⇛ ~ = 90° - &

• ⇛ ~ + & = 90°

Additional Information :-

$\rm :\longmapsto\: \boxed{ \sf \: cosx = sin(90 \degree \: - x)}$

$\rm :\longmapsto\: \boxed{ \sf \: tanx = cot(90 \degree \: - x)}$

$\rm :\longmapsto\: \boxed{ \sf \: cotx = tan(90 \degree \: - x)}$

$\rm :\longmapsto\: \boxed{ \sf \: secx = cosec(90 \degree \: - x)}$

$\rm :\longmapsto\: \boxed{ \sf \: cosecx = sec(90 \degree \: - x)}$