Question

If sin+cos=p and sec+cosec=q then prove that q(p^2-1)=2p

Answer 1

HELLO DEAR,


q(p2-1) = 2p

=>LHS = q(p2-1)

=>sec +cosec [(sin + cos)2-1



=> (sec+cosec) [sin2+cos2+2sin.cos -1]




= >(1/cos +1/sin) [1+2sin.cos-1]

{{identity: sin2=cos2=1}}



taking LCM of 1/sin + 1/cos


=> (sin +cos /sin.cos)[2sin.cos]




= >sin + cos / sin.cos * 2sin.cos



=> 2(sin + cos)


= >2(p) {{sin + cos = p


:(given in question)}}



Therefore 2p i.e. = RHS



hence, 2p = 2p

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Answer:

refer to the pic

Step-by-step explanation:

hope it help...