If sinθ=cosθ where (0°<θ<90°) then find tanθ+cotθ.
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tan theta+ cot theta=2
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sinø = cosø
therefore sinø/cosø = 1 ....(1)
Also cosø/sinø = 1 .....(2)
now, tanø = 1 ...from(1)
cotø = 1 ....from(2)
therefore tanø+cotø = 2
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