Question

If sin θ + cosec θ = 2 then,
(The remaining question is in pic).

Please answer ASAP

Answer 1

using x instead of theta
given :- sinx+1/sinx=2(cosec x=1/sinx)

Explanation:

Solving

sinx+1/sinx=2→sin2x−2sinx+1=0
we have

sinx=1 then

sin^nx+1sin^nx=2

Answer 2

Sin Ф + Cosec Ф = 2
(Sin²Ф + 1)/Sin Ф = 2
Sin²Ф - 2 sinФ  + 1 = 0

SinФ = 1
So Cosec Ф = 1.

So for any power n,  Sinⁿ Ф+ Cosecⁿ Ф = 2