Question

If sin inverse a + sin inverse b + sing inverse g = 3pi/4 then ab +ag+ bg is equal to?​

Answer 1

Answer:

1/4-1/2(a^2+b^2+c^2)

Step-by-step explanation:

= 3pi/4

sin inverse a + sin inverse b + sing inverse g

sin{sin inverse a + sin inverse b + sing inverse g}=sin 3pie/4

a+b+g=1/√2

(a+b+g)^2=(1/√2)^2

a^2+b^2+ g^2+2(ab+bg+ag)=1/2

2ab+bg+ag=1/2-(a^2+b^2+ g^2)

ab+bg+ag=1/4-1/2(a^2+b^2+g^2)