Question

if=sin inverse x, then range of y is

Answer 1

Answer:

[-π/2 to π/2]

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

$sin^{-1}x=y$

we know that

Range of principle Value of sin is $[-\pi /2,\pi/2]$

So$-\pi/2\leq y\leq \pi /2$