Question

if sin is equal to 3 upon 4 then calculate sec a​

Answer 1

Answer:

$\mathsf{secA=\frac{4}{\sqrt7}}$

Step-by-step explanation:

$\textsf{Given:}$

$\mathsf{sinA=\frac{3}{4}}$

$\textsf{Using}$

$\boxed{\mathsf{sin^2\theta+cos^2\theta=1\implies\,cos^2\theta=1-sin^2\theta}}$

$\mathsf{cos^2A=1-sin^2A}$

$\mathsf{cos^2A=1-\frac{9}{16}}$

$\mathsf{cos^2A=\frac{16-9}{16}}$

$\mathsf{cos^2A=\frac{7}{16}}$

$\mathsf{cosA=\frac{\sqrt7}{4}}$

$\textsf{Taking reciprocals, we get}$

$\therefore\mathsf{secA=\frac{4}{\sqrt7}}$

Answer 2

Answer:

Step-by-step explanation:

Sin A =3/4=P/H

B=root 16-9

B=root 7

SecA =H/B=4/root 7