if sin is equals to root 3 by 2 find the value of 2 cot square A minus one
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Answer:
Step-by-step explanation:
sin A = √3/2sin A = sin 60°A = 60°
Now, cot A = cot 60° = 1/√3
2cot² A - 1 = 2cot² 60° - 1= 2(1/√3)² - 1= 2/3 - 1 = -1/3
Hence your required answer is -1/3
Hope This Helps You!
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heya,
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akshatit:
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