Question

if sin O=12/13,evaluate secO+tanO/secO-tanO​

Answer 1

Answer:

25

Step-by-step explanation:

Sin O = 12/13

Sec O + tan O = 1/Cos O + Sin O/Cos O = 1+Sin O/Cos O

Sec O - tan O = 1/Cos O - Sin O/Cos O = 1-Sin O/Cos O

Therefore,    $\frac{Sec O + Tan O}{Sec O - Tan O}$   =  $\frac{1+Sin O/Cos O}{1-Sin O/Cos O}$   = 1+Sin O/1-Sin O = $\frac{13/13 + 12/13}{13/13 - 12/13}$ = $\frac{25/13}{1/13}$=25/1 = 25