Question

if sin Ø=12/13 then prove that​

Answer 1

Answer:

Step-by-step explanation:

given sint=12/13

tant=12/5

cott=5/12

cosect=13/12

cost=5/13

sect=13/5

LHS:

5tant-12cosect+13sint/(26cost+24cott-10sect)

5tant=5*12/5=12

12coset=12*13/12=13

13sint=13*12/13=12

26cost=26*5/13=10

24cott=24*5/12=10

10sect=10*13/5=26

numerator:5tant-12coesct+13sint=12-13+12=24-13=11

denominaotr: 26cost+24cott-10sect=10+10-26=-6

just check it  im getting -11/6