if sin Q = 1/3 then find the value of 2 cot Q
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sin Q = 1/3
so, cosec Q = 3
so, cosec² Q = 9
so, 1 + cot² Q = cosec² Q
hence cot² Q = 9-1 = 8
so, cot Q = √8
so, 2*cot Q = 2√8
= 4√2
so, cosec Q = 3
so, cosec² Q = 9
so, 1 + cot² Q = cosec² Q
hence cot² Q = 9-1 = 8
so, cot Q = √8
so, 2*cot Q = 2√8
= 4√2
rohiki1234:
please send me figure in this question
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sin=1/3
cosec= 3
cosec2= 9
cosec2= cot2+1
9= cot2+1
cot2=8
cot=√8
2cot= 2√8
2cot=4√2
cosec= 3
cosec2= 9
cosec2= cot2+1
9= cot2+1
cot2=8
cot=√8
2cot= 2√8
2cot=4√2
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