Question

If sin Q = 12/13, find tan Q​

Answer 1

Answer:

$\large\bf\underline\green{Answer}$

$\sin(Q) = \frac{12}{13}$

We know that,

$\sin = \frac{P}{H}$

P = 12

H = 13

By Pythagoras theorem,

H² = P² + B²

(13) ² = (12) ² + B²

169 = 144 + B²

B² = 169 - 144

B² = 25

B =√25

B = 5

➡$\cos(Q) = \frac{B}{H} \\ = \frac{5}{13}$

➡$\tan(Q) = \frac{ \sin(Q) }{ \cos(Q) } \\ = \frac{ \frac{12}{13} }{ \frac{5}{13} } \\ = \frac{12}{5}$

Or

$\tan(Q) = \frac{P}{B} \\ = \frac{12}{5}$

PLEASE MARK BRAINILIEST

Answer 2

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