Math, asked by chandrashissahamng71, 1 month ago

If sin Q =12÷13 Then evaluate (2sinQ-3 cos Q÷4 sin Q -9 cos Q) ​

Answers

Answered by MysticSohamS
2

Answer:

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Step-by-step explanation:

so here sin Q=12/13

so using

Sin.square Q+cos square Q=1

ie cos.square=1-sin.square Q

=1-(12/13)square

=1-144/169

=169-144/169

=25/169

taking square roots on both sides we get

cos Q=5/13

now substituting these values in

2sinQ-3 cos Q÷4 sin Q -9 cos Q

we get

=(2×12/13-3×5/13)÷(4×12/13-9×5/13)

=(24/13-15/13)÷(48/13-45/13)

=(24-15/13)÷(48-45/13)

=9/13÷3/13

=9/3

=3

hence value of 2sinQ-3 cos Q÷4 sin Q -9 cos Q is 3

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