If sin Q =12÷13 Then evaluate (2sinQ-3 cos Q÷4 sin Q -9 cos Q)
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Step-by-step explanation:
so here sin Q=12/13
so using
Sin.square Q+cos square Q=1
ie cos.square=1-sin.square Q
=1-(12/13)square
=1-144/169
=169-144/169
=25/169
taking square roots on both sides we get
cos Q=5/13
now substituting these values in
2sinQ-3 cos Q÷4 sin Q -9 cos Q
we get
=(2×12/13-3×5/13)÷(4×12/13-9×5/13)
=(24/13-15/13)÷(48/13-45/13)
=(24-15/13)÷(48-45/13)
=9/13÷3/13
=9/3
=3
hence value of 2sinQ-3 cos Q÷4 sin Q -9 cos Q is 3
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