if sin Q=√3cosQ,find all the 6 ratios
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sinQ=root3 cosQ
sinQ/cosQ=root3
tanQ=root 3 because sin/cos=tan
perpendicular = root3
base=1
hypotenuse=2(by pythagoras theorem)
sinQ=root3/2
cosQ=1/2
TanQ=root3/1
cosecQ=2/root3
secQ=2/1
cotQ=1/root3
khushi71203:
tanQ=p/b
we have tanQ=root3
if we have any number like 2 or3 we can write it2/1 or3/1
you know this fact??
yes of course
i got it
thanks
ok
welcome
mark it as brainliest answer
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