Question

If sin r1 = 1/3 , sin r2 = 1/1.5√2 and sin r3=√3/3 , find r1 , r2 and r3.​

Answer 1

Explanation:

(r1+e2)(r2+r3)(3+1)

r(1+2)(2+3)3+1)

r×3×5×4

r×(60)