If sin [ sin -¹ 2/5 + cos -¹ x ] =1 then find the value of x
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Answer:
cos(sin−152+cos−1x)=0
⇒sin−152+cos−1x=cos−10
⇒sin−152+cos−1x=2π
⇒sin−152=2π−cos−1x
⇒52=sin(2π−cos−1x)
⇒52=cos(cos−1x)
⇒x=52
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