if sin(sin inverse 1/5+cos inverse x) = 1, find x
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Hey there !!!!
sin(sin⁻¹1/5+cos⁻¹x)=1
sin⁻¹1/5+cos⁻¹x=sin⁻¹1
But sinπ/2=1
sin⁻¹1=π/2
So,
sin⁻¹1/5+cos⁻¹x=π/2-------------------Equation 1
In inverse trigonometry
sin⁻¹t+cos⁻¹t=π/2
So, equation 1 follows the above identity
So, sin⁻¹ 1/5+cos⁻¹x=π/2
Therefore value of x will be 1/5.
sin(sin⁻¹1/5+cos⁻¹x)=1
sin⁻¹1/5+cos⁻¹x=sin⁻¹1
But sinπ/2=1
sin⁻¹1=π/2
So,
sin⁻¹1/5+cos⁻¹x=π/2-------------------Equation 1
In inverse trigonometry
sin⁻¹t+cos⁻¹t=π/2
So, equation 1 follows the above identity
So, sin⁻¹ 1/5+cos⁻¹x=π/2
Therefore value of x will be 1/5.
8764:
thnk u so much
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