if sin[sin inverse1/5+cos inverse x)=1.Answer please♥️☺
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Hey there !!!!
sin(sin⁻¹1/5+cos⁻¹x)=1
sin⁻¹1/5+cos⁻¹x=sin⁻¹1
But sinπ/2=1
⇒sin⁻¹1=π/2
So,
sin⁻¹1/5+cos⁻¹x=π/2--------Equation 1
In inverse trigonometry
sin⁻¹t+cos⁻¹t=π/2
So, equation 1 follows the above identity
So, sin⁻¹ 1/5+cos⁻¹x=π/2
Therefore value of x will be 1/5.
Hope this helped you .....
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