Question

If sinθ + sin²θ = 1, find the value of cos^{12}θ + 3cos^10θ + 3cos^8θ + cos^6θ +2cos^4θ + 2cos²θ − 2.

Answer 1

Answer:

Step-by-step explanation:

Given : sin θ + sin2 θ = 1 ⇒ sin θ = 1 – sin2 θ Taking LHS = cos2θ + cos4θ = cos2 θ + (cos2 θ)2 = (1– sin2 θ) + (1– sin2 θ)2 …(i) Putting sin θ = 1 – sin2 θ in Eq. (i), we get = sin θ + (sin θ)2 = sin θ + sin2 θ = 1 [Given: sin θ + sin2 θ = 1] = RHS Hence ProvedRead more on Sarthaks.com - https://www.sarthaks.com/930499/if-sin-sin-2-1-then-prove-that-cos-2-1-cos-4-1

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Answer 2

Answer:

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