if sin square theta=7/25 find the values of cos square theta and tan square theta
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i am using @ = theta ok
sin@= p/h here sin@= 7/25 that means
we have a right angled triangle of hypotenuse 25 and perpendicular of 7
know at first we have to find base =?
b=24 ( by phythagoraus theorem )
now we have p=7 , b=24, and h=25
cos@=b/h therefore cos@=24/25
tan@=p/b therefore tan@=7/24
sin@= p/h here sin@= 7/25 that means
we have a right angled triangle of hypotenuse 25 and perpendicular of 7
know at first we have to find base =?
b=24 ( by phythagoraus theorem )
now we have p=7 , b=24, and h=25
cos@=b/h therefore cos@=24/25
tan@=p/b therefore tan@=7/24
AkashMnG:
tnx
wlcm
sin@/cos@ kaise
pls
sin@ = 7/25 hai cos@ 24/ 25 ayega
sin@/cos@ = 7/24 ayega
kaise ayega lekin
cos@= under root 1 - sin^2@
isse cos@ ayega
thik h
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