Question

If sin t + cos t = P , sec t + cosec t = Q , then find
Q ( P - 1 ) ( P + 1 )​

Answer 1

Answer:

sint +cost=p

.

sect+cosect=Q

.

Q(p-1)(p+1)

.

a^2-b^2=(a+b)(a-b)

.

Q(p^2-(1)^2)

.

Q[sin^2t+cos^2t-1]

.

Q(1-1)

::sin^2+cos^2=1

.

sect+cosect×0

=0.

THIS IS THE ANSWER =0... I HOPE IT HELP TO YOU