If sin teeta=6/10 then the value of tan teeta + sec teeta is
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2
sin ² theta + cos ² theta = 1
therfore,
(6/10)² + cos² theta = 1
cos² theta = 1 - 36/100
cos² theta = 100-36/100
cos theta = √64/100
cos theta = 8/10
therefore tan theta = sin theta/cos theta
= 6/10/8/10 = 6/8
sec theta = 1/cos theta
= 10/8
therefore,
6/8 - 10/8
= 4/8
= 2/4
Answered by
1
Answer:
Answer is 2
Explanation:
sinθ = 6/10
cosθ=√1-(6/10)²=8/10
tanθ=sinθ/cosθ=3/4
secθ=1/cosθ=10/8=5/4
tanθ+secθ=3/4 + 5/4 = 2
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