If
sin(teeta)+ cos(teeta )= root 2, then evaluate : tan(teeta) + cot(teeta)
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Answered by
5
The anser is in the pic..
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maksednoobie:
thank u soo much. how and from where u r finding ans?. trigonometry is hard(the last exercise especially) how and frm where to learn plz guide me
bro..keep calm....trigonometry i think is the easiest part of Mathematics...u just need to remember the basics and one important thing is that u have to imagine....
but last exercise we multiply something with same numerator and denominator...its so hard. r u in grade 10?? plz help me
yeah..i m in 10th grade
Don't worry...just u have to practice and practice and practice..
u will find it..easy...Moreover..i am also there to help u out
Answered by
4
Let theta=x
sinx+cosx=√2
squaring both side..
sin²x+cos²x+2sinxcosx=(√2)²
1+2sinxcosx=2
sinxcosx=1/2. ____(i)
Now ,
tanx+cotx=sinx/cosx + cosx/sinx
=(sin²x+cos²x)/sinxcosx
=1/(1/2) = 2 (from eq (i))
sinx+cosx=√2
squaring both side..
sin²x+cos²x+2sinxcosx=(√2)²
1+2sinxcosx=2
sinxcosx=1/2. ____(i)
Now ,
tanx+cotx=sinx/cosx + cosx/sinx
=(sin²x+cos²x)/sinxcosx
=1/(1/2) = 2 (from eq (i))
thank u soo much. how and from where u r finding ans?. trigonometry is hard(the last exercise especially) how and frm where to learn plz guide me
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