if sin Tera is equal 13 upon 12 find the values other trigonometric
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Hiii friend,
IT SEEMS YOUR QUESTION IS INCORRECT
IT SHOULD BE SIN THETA = 12/13
Sin theta = 12/13 = P/H
P = 12 , H = 13
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)² = (13)² - (12)² = 169 - 144 = 25
B = ✓25 = 5
Therefore,
Sin theta = P/H = 12/5
Cos theta = B/H = 5/13
Tan theta = P/B = 12/5
Cot theta = B/P = 5/12
Cosec theta = H/P = 5/12
Sec theta = H/B = 13/5
HOPE IT WILL HELP YOU...... :-)
IT SEEMS YOUR QUESTION IS INCORRECT
IT SHOULD BE SIN THETA = 12/13
Sin theta = 12/13 = P/H
P = 12 , H = 13
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)² = (13)² - (12)² = 169 - 144 = 25
B = ✓25 = 5
Therefore,
Sin theta = P/H = 12/5
Cos theta = B/H = 5/13
Tan theta = P/B = 12/5
Cot theta = B/P = 5/12
Cosec theta = H/P = 5/12
Sec theta = H/B = 13/5
HOPE IT WILL HELP YOU...... :-)
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