Math, asked by mustafaisal92, 1 year ago

If sin teta+cos teta =root2 sin (90--0) then find the value of cotteta

Answers

Answered by spiderman2019

1

Answer:

√2 + 1

Step-by-step explanation:

sinθ+cosθ = √2 sin (90-θ)

=> sinθ+cosθ = √2Cosθ

=> Sinθ = (√2 - 1)Cosθ

=> Cotθ = 1/√2 - 1 = √2 + 1.

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