Question

If sin$\theta$ = $\frac{\sqrt{3}}{\sqrt{5}}$ and cos$\theta$ = $\frac{\sqrt{2}}{\sqrt{5}}$
Find cot$\theta$

Answer 1

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If sin$\theta$ = $\frac{\sqrt{3}}{\sqrt{5}}$ and cos$\theta$ = $\frac{\sqrt{2}}{\sqrt{5}}$

Find cot$\theta$

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$\sf sin\theta=frac{\sqrt{3}}{\sqrt{5}}$

$\sf sin\theta=\frac{opposite}{hypotenuse}$

$\sf cos\theta=frac{\sqrt{2}}{\sqrt{5}}$

$\sf sin\theta=\frac{adjacent}{hypotenuse}$

1. $\sf opposite = \sqrt{3}$
2. $\sf adjacent = \sqrt{2}$
3. $\sf hypotenuse = \sqrt{5}$

$\sf cot\theta=\frac{adjacent}{opposite}$

${\boxed {\sf\therefore cot\theta=\frac{\sqrt{2}}{\sqrt{3}}}}$

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