Question

If sin theda = -4/5, Theda is Iv quadrant
find
3cos theda - 4 tan theda​

Answer 1

Step-by-step explanation:

Sin theta= -4/5

By Pythagoras theorem, we will find the base

B²=5²-(-4²)

B²=25-16

B=√9

B= 3

so Cos theta and tan theta will be,

3/5 & 4/3 respectively.

According to the question,

3×3/5 = 9/5 4×-4/3 = -16/3

9/5-(-16/3)= 7.13