Question

If sin theeta =1/3 , then tan theeta =

Answer 1

Question :-

If sin θ = 1/3 , then find the value of tan θ.

Answer :-

let sin θ = (1k/3k) .

We have ,

sin θ = AC / AB

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Therefore,

• AC = k

• AB = 3k

And,

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BC = √ AB² - AC²

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= √ (3k)² - (k)²

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= √ 9k² - k²

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= √ 8k²

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= 2√2 k

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Thus,

tan θ = AB / BC

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= k / 2√2 k

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tan θ = 1 / 2√2

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.. Thank You !!

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